Official help for 8b
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02 Jan 18 at 6:54 pm #34019AnonymousInactive
Any clues for that secret message?
02 Jan 18 at 6:55 pm #34020AnonymousInactiveBut how do you know the beginning and end of words?
P.S. Thank you very much to anyone who answered my previous question.
Koala
02 Jan 18 at 6:56 pm #34022AnonymousInactiveWas almost ready to give up but then reread the clue by @Lineage Noir a couple hundreds times and finally worked it out.
Just keep at it and try as many possibilities as you can.02 Jan 18 at 7:09 pm #34030AnonymousInactiveOFFICIAL CLUE: First, reverse each word, but keep them in the same order, e.g. “I am Joan.” Would become “I ma naoJ.” Then decode bearing in mind it was encoded using the following method. Leave the first letter as it is. The second letter is the first plus the second added together. The third, is the second plus the third added together. Continue till you have done 12 letters, then repeat (so every 12th letter is already correct).
This could also be solved as a Hill cipher using a 12 by 12 matrix where the first row is 1 followed by 11 0s), the second is 1 1 followed by 10 0s, the third row is 0 1 1 followed by 9 0s etc.
Clues for the secret message will be posted in a separate forum.
02 Jan 18 at 9:12 pm #34032AnonymousInactivewhat does “os” mean
02 Jan 18 at 9:12 pm #34033AnonymousInactiveWhat am I doing wrong? First letter is correct, Y. Next letter, currently C, is actually (value of Y) – (value of C) = 25 – 3 = 22 = V. Next letter, currently E, is actually 22 – 5 = Q. YVQ – doesn’t seem like this is going anywhere. What am I doing wrong, this is probably a silly mistake.
PS Joan, did you mean that the third row is 111 following by 9 0s? i.e.
100000000000
110000000000
111000000000
111100000000
111110000000
111111000000
111111100000
111111110000
111111111000
111111111100
111111111110
111111111111As the matrix?
02 Jan 18 at 9:13 pm #34034AnonymousInactiveHow do you “add” the letters?
02 Jan 18 at 11:59 pm #34039AnonymousInactive@Nebuler,
Joan said “0 1 1 followed by 9 os”
…
02 Jan 18 at 11:59 pm #34040AnonymousInactiveI think that it is plaintext = ciphertext – keytext, using A=0, B=1, C=2 etc, and mod 26 arithmetic
Thus the second letter of plaintext will be C – Y, which is 2 -24, which is 4 (mod 26) and thus the second letter of the plaintext is E, which makes more sense 🙂
03 Jan 18 at 12:00 am #34041AnonymousInactiveNoaj, Noaj, Noaj (it’s Joan backwards)
No wonder this is set by the University of Southampton, you’ve really pushed the boat out on this one
Danke für die Herausforderung.
03 Jan 18 at 12:00 am #34042AnonymousInactive0s is zero’s not os as it looks like in this font
03 Jan 18 at 1:04 pm #34049AnonymousInactiveIs it
100000000000
110000000000
011000000000
001100000000
000110000000
000011000000
000001100000
000000110000
000000011000
000000001100
000000000110
000000000011Am I close.
Also what comes after the forth of January. Do the best get picked03 Jan 18 at 1:06 pm #34050AnonymousInactiveDesperately trying to limp to the finish line here (the white flag of surrender has been hoisted for some time now!!). I have followed, with immense gratitude, Joan’s (and others) hints and tips but am still fumbling in the dark.
I have reversed the letter order but maintained the word order, so the first word was originally TVVERECY, and reversed reads YCEREVVT. I have then used the method explained by @Tommo above, which gives me a decode of YECNNRAY.
I am happy to keep on plodding on with my decode, but at the moment, it aint making much sense!! If I am going wrong somewhere, please can SKS point me in the right direction?
Thanks!
03 Jan 18 at 1:06 pm #34051AnonymousInactivei got 99.99 what more
03 Jan 18 at 1:09 pm #34056AnonymousInactiveJoan, when you say the third letter is encrypted by adding the second to the third, does this mean the second after it’s been encrypted or before?
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