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This topic contains 191 replies, has 48 voices, and was last updated by  Anonymous 2 years, 4 months ago.

Viewing 13 posts - 181 through 193 (of 193 total)
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  • #34104

    Anonymous

    @Cristina sorry for not replying, yes those numbers look correct.

    #34106

    Anonymous

    Thanks Joan, I think I’m reversing wrong
    Does anyone here have any tips for programming it on excel or word?

    #34108

    Anonymous

    @cristina Remember that the matrix that you have is the ENCRYPTION matrix. To decrypt, you will need the inverse matrix of the encryption matrix.

    #34109

    Anonymous

    That feeling when today is the last deadline and you have still got no idea on how to solve this…

    #34121

    Anonymous

    I don’t get this!!!!!!

    #34122

    Anonymous

    Please help someone I need to complete it now

    #34123

    Anonymous

    @Lineage Noir thanks so much, I forgot, but what do you mean inverse matrix?
    Thanks

    #34124

    Anonymous

    Wait so, you reverse each word, then you do Hill Cipher with matrices I posted before but reversed?
    If yes, it doesn’t seem to work.

    #34133

    Anonymous

    I’ve done everything above, reversed each word’s lettering and tried decoding it with a Hill cipher with inversed matrices. However, I get a load of rubbish back with the occasional word in it. Any clues as to what I’m doing wrong?

    #34132

    Anonymous

    Text Mechanic is a very useful tool for what you suggest, and other things.

    #34144

    Anonymous

    @cristina The encryption is done by multiplying the encoding or key matrix by series of characters (or the numbers 0-25 representing them) Modulo 26.

    Intuitively we should be able to decrypt the ciphertext dividing by the key matrix. However, matrix division is not possible, so we use an inverse matrix.

    With numbers consider multiplying a number by its reciprocal 2 x ½ =1. With a matrix, when we multiply by its inverse, we get the identity matrix I. (Think of this as the matrix equivalent of 1. It is a square matrix full of zeros except the top left to bottom right diagonal which are all 1s).

    Matrices in mathematics are usually on the curriculum of “A” level maths and Further Pure maths, so don’t beat yourself up if you haven’t got to grip with them (yet), congratulate yourself on the progress that you have made and maybe try one of the non-matrix approaches.

    Good luck. Tempus fugit!

    #34139

    Anonymous

    Cristina I don’t know if your having trouble with reversing of the words, or with the hill cipheriness.
    For the reversing, I would suggest having each word on a seperate line in excel (replacing spaces with paragraph marks in word should do this)
    The I would use the mid function, but instead of going 1, 2, 3, 4, go 15, 14, 13, 12… (you’ll get a few #VALUE! cells when pasted back into word, but a quick replace should get rid of these)

    I would then create a new spreadsheet for the hill cipher solving.
    Use MID and VLOOKUP to write the cipher out in numbers (A=0, Z=25), 12 to a row

    Then you’ll want to do the cipher text number – previous plaintext number. (sorry if thats not clear it’s weird to explain)
    Finally use MOD(cell, 26) to convert your deciphered numbers to numbers between 0-25.

    Use VLOOKUP to convert back to A-Z.

    Hopefully I didn’t confuse you even more :/

    #34150

    Anonymous

    Thanks so much guys, got higher than before but not 100.

Viewing 13 posts - 181 through 193 (of 193 total)

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