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Official help for 7b

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  • 08 Dec 17 at 3:19 pm #33474
    Anonymous
    Inactive

    OFFICIAL CLUE: The number you need to know for the scytale is … 6.

    10 Dec 17 at 12:44 am #33482
    Anonymous
    Inactive

    6. A nice number there, the second prime, whereas 2 is the first prime. 13 is the next number in the sequence.

    10 Dec 17 at 1:28 pm #33486
    Anonymous
    Inactive

    WHERE DO THE IS AND BS SHOW UP?

    10 Dec 17 at 5:53 pm #33489
    Anonymous
    Inactive

    OFFICIAL CLUE: The I’s and B’s contained a secret message, “SCYTALE SECURITATEM PRAEBET AMPLIUS”.

    11 Dec 17 at 11:58 am #33494
    Anonymous
    Inactive

    Can we have any more clues?

    11 Dec 17 at 9:49 pm #33501
    Anonymous
    Inactive

    You really don’t need any more clues. It uses a scytale of 6. You should be able to figure out what the secondary cipher is as it isn’t anything new to you.

    12 Dec 17 at 12:27 am #33507
    Anonymous
    Inactive

    Wait so this is double enciphered meaning that the first one is syctale, so we encrypt that and then we need to figure out the other one and encrypt that message to figure out 7b????

    12 Dec 17 at 3:00 am #33510
    Anonymous
    Inactive

    OFFICIAL CLUE: The second cipher has keyword length 7.

    12 Dec 17 at 2:01 pm #33511
    Anonymous
    Inactive

    We’ve done it. Think about previous times and the ciphers you used
    We’re 9. If we can do it, so can you.

    12 Dec 17 at 2:06 pm #33516
    Anonymous
    Inactive

    OFFICIAL CLUE: Most of this has been already given out in clues, but at least it is all together now. The first cipher you need to decode is scytale, with rod size 6. The second is Vigenere and the keyword is 7 characters. The secret message with the I’s and B’s was “SCYTALE SECURITATEM PRAEBET AMPLIUS”. I suggest you look to translate this as it gives you one final clue.

    13 Dec 17 at 2:01 pm #33528
    Anonymous
    Inactive

    How does it work because it is not divisible by 6

    13 Dec 17 at 2:02 pm #33529
    Anonymous
    Inactive

    Sorry, I meant 7 not 6

    13 Dec 17 at 11:59 pm #33536
    Anonymous
    Inactive

    @67105112104101114, look at the cipher carefully for other symbols.

    14 Dec 17 at 12:00 am #33537
    Anonymous
    Inactive

    Strip out the spaces then check the position (indices) of the underscores in the cipher, in particular the spacing of them. That should give you a clue.

    14 Dec 17 at 12:01 am #33539
    Anonymous
    Inactive

    Does a rod size of 6 mean that there are 6 lines or each line has 6 characters?

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