Skip to main content

Official help for 6b

Home › Forums › The Sixteenth National Cipher Challenge: The Lost Legion › Official help for 6b

Viewing 15 posts - 106 through 120 (of 127 total)
1 2 3 … 7 8 9
  • Author
    Posts
  • 26 Nov 17 at 11:32 am #33126
    Anonymous
    Inactive

    Funny, I swear Agricola was also a word in a certain language…

    27 Nov 17 at 4:24 pm #33137
    Anonymous
    Inactive

    Anybody know how the two ciphers are combined??

    27 Nov 17 at 4:24 pm #33139
    Anonymous
    Inactive

    I can’t see a way to translate death of farmer that has 15 letters instead of 14.

    27 Nov 17 at 5:26 pm #33147
    Anonymous
    Inactive

    @Strider

    Joan said ‘Farmer’s Death’

    27 Nov 17 at 7:09 pm #33149
    Anonymous
    Inactive

    Just try previous Languages the keywords were in, and translate ‘farmer’s death’ into that

    27 Nov 17 at 7:46 pm #33151
    Anonymous
    Inactive

    Do we get any more clues?? Pls we need help.
    Open to suggestions

    27 Nov 17 at 9:01 pm #33154
    Anonymous
    Inactive

    @strider hint: it’s not nominative

    28 Nov 17 at 3:22 am #33159
    Anonymous
    Inactive

    OFFICIAL HINT: The key word for the vigenere is “Agricolae mortem”. Once you have decoded this, you need to decode the affine shift too.

    28 Nov 17 at 12:04 pm #33160
    Anonymous
    Inactive

    How do I find which part of the cipher is Vigenere and which is affine shift?

    28 Nov 17 at 3:56 pm #33164
    Anonymous
    Inactive

    Stuck on the same thing… just tried doing it layer by layer (Vigenere then affine shift) but it yielded utter nonsense…

    28 Nov 17 at 3:58 pm #33167
    Anonymous
    Inactive

    OFFICIAL CLUE: It was encoded first by an affine shift of x -> 7x. Then the result of this was encoded with a vigenere. Hope this solves the problems.

    28 Nov 17 at 7:55 pm #33170
    Anonymous
    Inactive

    how would this be written as in key form?

    28 Nov 17 at 10:43 pm #33172
    Anonymous
    Inactive

    What does x->7x mean??

    29 Nov 17 at 2:03 pm #33174
    Anonymous
    Inactive

    It means if you convert a letter (say, d) into its number equivalent (4), then multiply it by 7 (28) and then find the remainder when it is divided by 26 (2), then convert that number back into a letter (b) then every time it (d) occurs in the plaintext it is represented by that letter you just calculated (b) in the ciphertext.

    Hope this helped!

    29 Nov 17 at 2:04 pm #33175
    Anonymous
    Inactive

    Check page 10 of Prof. Graham A. Niblo’s “A beginner’s guide to codebreaking” on this site.

    https://2017.cipherchallenge.org/wp-content/uploads/2016/10/A-beginners-guide-to-codebreaking-1.1b.pdf

  • Author
    Posts
Viewing 15 posts - 106 through 120 (of 127 total)
1 2 3 … 7 8 9
  • You must be logged in to reply to this topic.